17-09-2017, 10:08 AM
The maths is pretty straightforward - with low HT, the electrons passing from cathode to anode have low speed and are moved off course easily... the electrons' velocity is directly proportional to the square root of the anode/cathode PD.
Basically, the energy gained by an electron caused by being exposed to potential difference (PD), E, is equal to Q*V, where "Q" is its charge, and "V" is the potential difference it's exposed to, so E is directly proportional to the PD - this is all kinetic energy.
Remember also the general-case kinetic energy equation E = 0.5 * m * v * v, ("m" is the mass of an electron) we re-arrange to get v (the velocity) = sqrroot(2E/m), so the velocity of the electrons is proportional to the square root of the electrons' energy, E, which means that the velocity is also directly proportional to the square root of the potential difference (see above).
Low B+ = low energy electrons = slow electrons = sensitivity to external fields...
Basically, the energy gained by an electron caused by being exposed to potential difference (PD), E, is equal to Q*V, where "Q" is its charge, and "V" is the potential difference it's exposed to, so E is directly proportional to the PD - this is all kinetic energy.
Remember also the general-case kinetic energy equation E = 0.5 * m * v * v, ("m" is the mass of an electron) we re-arrange to get v (the velocity) = sqrroot(2E/m), so the velocity of the electrons is proportional to the square root of the electrons' energy, E, which means that the velocity is also directly proportional to the square root of the potential difference (see above).
Low B+ = low energy electrons = slow electrons = sensitivity to external fields...
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