16-05-2017, 09:32 PM
OK, so that's a beta of 200. Emitter current will indeed be the sum (6.03mA).
To apply Ohm's law, you need to know the voltage across each resistor. So your scenario needs a bit more detail adding. To help, I'll give you an example:
Let's assume a supply voltage of 9V, and a silicon transistor. I'm also assuming that emitter is connected to ground.
To get 30uA in the base, you need a 287k resistor. That one is pretty easy to work out - I'll leave that to you to figure out and explain to us.
The collector voltage is more tricky because the scenario hasn't stated the desired collector voltage. In which case, I'll assume 4.5V. Having added that assumption, calculating the load resistor is so easy that I won't do it... Over to you.
Does that help? Do you want to outline your scenario, complete with the missing details that I've just mentioned, so we can double-check your understanding?
To apply Ohm's law, you need to know the voltage across each resistor. So your scenario needs a bit more detail adding. To help, I'll give you an example:
Let's assume a supply voltage of 9V, and a silicon transistor. I'm also assuming that emitter is connected to ground.
To get 30uA in the base, you need a 287k resistor. That one is pretty easy to work out - I'll leave that to you to figure out and explain to us.
The collector voltage is more tricky because the scenario hasn't stated the desired collector voltage. In which case, I'll assume 4.5V. Having added that assumption, calculating the load resistor is so easy that I won't do it... Over to you.
Does that help? Do you want to outline your scenario, complete with the missing details that I've just mentioned, so we can double-check your understanding?
