03-03-2017, 02:18 AM
Looking at Mark's diagram probably I'm just not used to transistor diagrams but I think what throws me is the resistances aren't on a common rail but via the transistor. So looking at the 9 V supply the current runs in series through the 47 k and the 10 K back to negative. That's series. Without any transistor at all we could have 57 K and 5700 K in parellel across the supply rails. Yet the 4700 and the 1K are not common to ground. Do you see the transistor load in series with the emitter load??? Alternatively what would happen if you used the total parallel resistance?
Going with what I know so far, the norm would be you'd have the HT current and voltages in the valve schematic and it would be easier I think.
Going with what I know so far, the norm would be you'd have the HT current and voltages in the valve schematic and it would be easier I think.







