28-03-2013, 12:57 PM
I am thinking along the lines of there being a mistake in the mathematics.
If a charged capacitor is connected to a discharged capacitor of the same value with the real life with losses ignored the final voltage will be half the initial voltage.
It id just a matter of capacitance multiplied by voltage in both cases.
The squareds and square roots have confused matters greatly.
There is only one tear of multiplication or division in both cases that i can see.
If a charged capacitor is connected to a discharged capacitor of the same value with the real life with losses ignored the final voltage will be half the initial voltage.
It id just a matter of capacitance multiplied by voltage in both cases.
The squareds and square roots have confused matters greatly.
There is only one tear of multiplication or division in both cases that i can see.
