26-08-2014, 03:09 PM
(This post was last modified: 26-08-2014, 03:10 PM by John M0GLN.)
I have been reading a few books on the subject of valve crystal oscillators and the importance of preventing the current through the crystal from rising too high and cracking it, in the book 'Amateur Radio, a beginners guide' by J Douglas Fortune he describes a method of judging the current by inserting a incandescent bulb in the control grid circuit and in a copy of the 'Radio Communication Handbook' they also suggest a similar bulb or a 60mA thermocouple meter, in the attached circuit scanned from the former book it shows this small bulb inserted in the control grid circuit, this is a Mazda R48 which is a 2V 60mA bulb, now I can't understand how enough current can flow from the control grid through this bulb to light it up, even dimly, I don't know what the control grid current of the 6F6G will be in this circuit but the maximum for the 6L6 final is only about 6mA, and the maximum anode current of the 6F6G is only in the 30's of mA.
So can anyone please tell me what I'm not understanding?
John
So can anyone please tell me what I'm not understanding?
John










