03-03-2017, 03:46 AM
4.3 would be 9 volts minus the 4.7 dropped by the 4700 load. There's another observation. Ok I got it. Let's assume we know the "tables" gave us 4.3 collector volts and supply is 9 volts. So we need to drop the difference between 9 and 4.3 which is 4.7. Divide the known 1 milliamp into the 4.7 to drop and you get 4700 R. That will be the "trick" question Mark aimed at me. I think it only confused me since normally the voLtage would already have given for a tube anode. It's almost 3.30 am so nobody can accuse me of not doing my bit. I am going to put the kettle on and watch a movie.
