03-03-2017, 01:42 AM
(This post was last modified: 03-03-2017, 01:49 AM by Nowhere-Man.)
I just noticed something that's relevant to this thread so I'll share it. I was just looking at the Saalburg diagram and something very simple struck me. I will share it now: Voltage dividers simply split the supply voltage but need to then be viewed distinctly in the contex of load and current. So if we have a supply of, say, 230 volts with 22K and 11K, the split potential will be 153 volts and 76 volts. Yet with loads placed across each divider, a wattage and current will create a drop across the load.
So, to calculate an anode potential we need a total series voltage plus the current. Thus in series the. 22 and 11K are just the required resistance.
My my point is the voltage divider is just a way to split volts but loads and current are going to have an effect.
So, if you know the supply voltage and the anode voltage the difference is the drop required. Divide the known current into the sum to drop. If it's say 100,000 R you can use three 33's.
So, to calculate an anode potential we need a total series voltage plus the current. Thus in series the. 22 and 11K are just the required resistance.
My my point is the voltage divider is just a way to split volts but loads and current are going to have an effect.
So, if you know the supply voltage and the anode voltage the difference is the drop required. Divide the known current into the sum to drop. If it's say 100,000 R you can use three 33's.
